![mixture: integral of { [ arcsin(sqrt(x)) - arccos(sqrt(x)) ] / [ arcsin (sqrt(x)) + arccos(sqrt(x))] } mixture: integral of { [ arcsin(sqrt(x)) - arccos(sqrt(x)) ] / [ arcsin (sqrt(x)) + arccos(sqrt(x))] }](https://4.bp.blogspot.com/-OCEj9DFF460/WIBn8pt8U8I/AAAAAAAABE4/NyfKHx9Ya6wPTTWTqr5yRGrnUhsLu_B7wCLcB/s1600/integration%2Bby%2Bparts%2B1.jpg)
mixture: integral of { [ arcsin(sqrt(x)) - arccos(sqrt(x)) ] / [ arcsin (sqrt(x)) + arccos(sqrt(x))] }
![If [math]\arcsin x + \arctan x = \frac{\pi}{2} [/math], how do I prove that [math]2x^2+1=\sqrt{5}[/math]? - Quora If [math]\arcsin x + \arctan x = \frac{\pi}{2} [/math], how do I prove that [math]2x^2+1=\sqrt{5}[/math]? - Quora](https://qph.cf2.quoracdn.net/main-qimg-0d1a35b1a56d1676851aeed30fc1d2e3.webp)
If [math]\arcsin x + \arctan x = \frac{\pi}{2} [/math], how do I prove that [math]2x^2+1=\sqrt{5}[/math]? - Quora
FUNCTIONS: Single Correct : Solution set of the equation, arccos(x) arcsine( x)= arccos(x*root(3)) A. Is a unit set B. Consists of two elements C. Consists of three elements D. Is a void set.
![Range of f(x)=sin^(-1)x+tan^(-1)x+sec^(-1)x is (a)(pi/4,(3pi)/4) (b) [pi/4,(3pi)/4] (c){pi/4,(3pi)/4} (d) none of these Range of f(x)=sin^(-1)x+tan^(-1)x+sec^(-1)x is (a)(pi/4,(3pi)/4) (b) [pi/4,(3pi)/4] (c){pi/4,(3pi)/4} (d) none of these](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/646268447_web.png)